315 / 371
Resolução
i)
Extracção com reposição
Para obter o espaço de resultados considere-se a seguinte tabela de dupla entrada
315
Probabilidade
Operações com acontecimentos
2ºcartão
1ºcartão
1
2
3
4
1
(1,1) (1,2) (1,3) (1,4)
2
(2,1) (2,2) (2,3) (2,4)
3
(3,1) (3,2) (3,3) (3,4)
4
(4,1) (4,2) (4,3) (4,4)
a)
S=
(1,1), (1,2), (1,3), (1,4), (2,1),
(2,2), (2,3), (2,4), (3,1), (3,2), (3,3),
(3,4), (4,1), (4,2), (4,3), (4,4)
b)
A=
(1,2), (1,4), (2,1), (2,3), (3,2),
(3,4), (4,1), (4,3)
B=
(2,2), (2,4), (4,2), (4,4)
C=
(1,2),(1,4),(2,1),(2,2) ,(2,3),(2,4),
(3,2), (3,4), (4,1), (4,2), (4,3), (4,4)
D=
(1,1), (2,2), (3,3), (4,4)
ii)
Extracção sem reposição
Na tabela anterior os resultados a sombreado não se podem verificar
a)
S=
(1,2), (1,3), (1,4), (2,1), (2,3), (2,4), (3,1), (3,2), (3,4), (4,1), (4,2), (4,3)
b)
A=
(1,2), (1,4), (2,1), (2,3), (3,2), (3,4), (4,1), (4,3)
B=
(2,4), (4,2)
C=
(1,2), (1,4), (2,1),(2,3),(2,4), (3,2), (3,4), (4,1), (4,2), (4,3)
D=
=Ø
Índice
Voltar
MAPA